A) 1
B) 2
C) 3
D) 4
Correct Answer: A
Solution :
[a] \[-\frac{dU}{dr}=F\] (conservative force field) \[\Rightarrow F=\frac{-K}{r}\] provides the centrifugal force for circular motion of electron. \[\frac{m{{v}^{2}}}{r}=\frac{K}{r}\Rightarrow r=\frac{nh}{2\pi \sqrt{mK}}\] K.E. of electron \[=\frac{1}{2}m{{v}^{2}}=\frac{1}{2}K\] P.E. of electron = K In r E(n)=Total energy=K.E.+P.E.You need to login to perform this action.
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