A) 27/32
B) 32/27
C) 4/9
D) 9/4
Correct Answer: A
Solution :
[a] \[\frac{1}{{{\lambda }_{3-1}}}=R\left( \frac{1}{{{1}^{2}}}-\frac{1}{{{3}^{2}}} \right)=\frac{8R}{9}\] \[\frac{1}{{{\lambda }_{2-1}}}=R\left( \frac{1}{{{1}^{2}}}-\frac{1}{{{2}^{2}}} \right)=\frac{3R}{4}\Rightarrow \frac{{{\lambda }_{3-1}}}{{{\lambda }_{2-1}}}=\frac{27}{32}\]You need to login to perform this action.
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