A) \[a=3b\]
B) \[a={{b}^{3}}\]
C) \[b={{a}^{3}}\]
D) None of these
Correct Answer: B
Solution :
[b] We have a = sum of the coefficient in the expansion of \[{{(1-3x+10{{x}^{2}})}^{n}}={{(1-3+10)}^{n}}\] \[={{(8)}^{n}}\] \[\Rightarrow {{(1-3x+10{{x}^{2}})}^{n}}={{(2)}^{3n}},\] [Putting \[x=1\]] Now, b = sum of the coefficient in the expansion of \[{{(1+{{x}^{2}})}^{n}}={{(1+1)}^{n}}=2n.\] clearly, \[a={{b}^{3}}\]
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