A) \[{{H}_{3}}\overset{+}{\mathop{N}}\,\overset{R}{\mathop{\overset{|}{\mathop{C}}\,}}\,HC{{O}_{2}}H\]
B) \[{{H}_{2}}\overset{{}}{\mathop{N}}\,\overset{R}{\mathop{\overset{|}{\mathop{C}}\,}}\,HC{{O}_{2}}H\]
C) \[{{H}_{3}}\overset{+}{\mathop{N}}\,\overset{R}{\mathop{\overset{|}{\mathop{C}}\,}}\,HC{{O}_{2}}\]
D) \[{{H}_{2}}\overset{{}}{\mathop{N}}\,\overset{R}{\mathop{\overset{|}{\mathop{C}}\,}}\,HCO_{2}^{-}\]
Correct Answer: A
Solution :
[a] In acidic medium Zwitter ion convert into \[\overset{+}{\mathop{N}}\,{{H}_{3}}-\underset{R}{\mathop{\underset{|}{\mathop{C}}\,}}\,H-CO{{O}^{-}}+{{H}^{+}}\] \[\xrightarrow{{}}\overset{+}{\mathop{N}}\,{{H}_{3}}-\underset{R}{\mathop{\underset{|}{\mathop{C}}\,}}\,H-COOH\]You need to login to perform this action.
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