A) 61.0%
B) 38.0%
C) 35.5%
D) 41.5%
Correct Answer: D
Solution :
[d] Given \[e=1.60\times {{10}^{-19}}C\] \[d=9.17\times {{10}^{-11}}m\] From \[\mu =e\times d\] \[\mu =1.60\times {{10}^{-19}}\times 9.17\times {{10}^{-11}}\] \[=14.672\times {{10}^{-30}}\] % ionic character \[=\frac{Observed\text{ }dipole\text{ }moment}{Calculated\text{ }Dipole\text{ }moment}\times 100\] \[=\frac{6.104\times {{10}^{-30}}}{14.672\times {{10}^{-30}}}\] \[=41.5%\] %You need to login to perform this action.
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