A) \[B{{F}_{3}},N{{F}_{3}},CO{{_{3}^{2}}^{-}}\]
B) \[CO_{3}^{2-}\text{, }NO_{3}^{-},\,\,S{{O}_{3}}\]
C) \[N{{H}_{3}},S{{O}_{3}},CO{{_{3}^{2}}^{-}}\]
D) \[NC{{l}_{3}},BC{{l}_{3}},S{{O}_{3}}\]
Correct Answer: B
Solution :
[b] Group Hybridization Shape |
(1) \[B{{F}_{3}}\] \[s{{p}^{2}}\] Triangular Planar (TP) |
\[N{{F}_{3}}\] \[s{{p}^{3}}\] Tetrahedral (T) |
\[CO_{3}^{2-}\] \[s{{p}^{2}}\] T.P. |
(2) \[\left. \begin{matrix} CO_{3}^{2-} & s{{p}^{2}} & T.P. \\ NO_{3}^{-} & s{{p}^{2}} & T.P. \\ S{{O}_{3}} & s{{p}^{2}} & T.P. \\ \end{matrix} \right\}\left( \begin{align} & \text{All}\,\,\text{have}\,\,\text{same}\, \\ & \text{hybridization} \\ \end{align} \right)\] |
(3) \[N{{H}_{3}}\] \[s{{p}^{3}}\] T.P. |
\[S{{O}_{3}}\] \[s{{p}^{2}}\] T.P. |
\[CO_{3}^{2-}\] \[s{{p}^{2}}\] T.P. |
(4) \[NC{{l}_{3}}\] \[s{{p}^{3}}\] T.P. |
\[BC{{l}_{3}}\] \[s{{p}^{2}}\] T.P. |
\[S{{O}_{3}}\] \[s{{p}^{2}}\] T.P. |
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