A) \[ds{{p}^{2}},ds{{p}^{3}},s{{p}^{2}}and\,s{{p}^{3}}\]
B) \[s{{p}^{3}},ds{{p}^{2}},s{{p}^{3}}d,s{{p}^{2}}\]
C) \[ds{{p}^{2}},s{{p}^{2}},s{{p}^{3}},ds{{p}^{3}}\]
D) \[ds{{p}^{2}},s{{p}^{3}},s{{p}^{2}},ds{{p}^{3}}\]
Correct Answer: B
Solution :
[b] Hybridisation in\[N{{H}_{3}}=s{{p}^{3}}\], \[{{[PtC{{l}_{4}}]}^{2-}}=ds{{p}^{2}}\] (inner complex); \[PC{{l}_{5}}=s{{p}^{3}}d\] and \[BC{{l}_{3}}\] is \[s{{p}^{2}}\].You need to login to perform this action.
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