A) In \[N_{2}^{+},N-N\] bond weakens
B) In \[O_{2}^{+}\], the \[O-O\] bond order increases
C) In \[O_{2}^{+}\], paramagnetism decreases
D) \[N_{2}^{+}\] becomes diamagnetic
Correct Answer: D
Solution :
[d] \[\sigma _{b}^{2}{{\sigma }^{*}}_{a}^{2}\sigma _{b}^{2}{{\sigma }^{*}}_{a}^{2}(\pi _{b}^{2}=\pi _{b}^{2})\,\sigma _{b}^{1}\,(N_{2}^{+}=13\,\text{electrons})\] it contains one unpaired electron hence paramagneticYou need to login to perform this action.
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