NEET Chemistry Chemical Kinetics / रासायनिक बलगतिकी Question Bank Self Evaluation Test - Chemical Kinetics

  • question_answer
    For a reaction, the rate constant is expressed as\[k=A{{e}^{-40000/T}}\]. The energy of the activation is

    A) 40000 cal        

    B) 88000 cal

    C) 80000 cal        

    D) 8000 cal

    Correct Answer: C

    Solution :

    [c] \[k=A{{e}^{-{{E}_{a}}/RT}}\] \[\therefore \frac{-{{E}_{a}}}{R}=-40000\] \[\therefore {{E}_{a}}=40000\times 2=80000\,cal\]


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