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NEET Chemistry Chemical Kinetics / रासायनिक बलगतिकी Question Bank Self Evaluation Test - Chemical Kinetics

  • question_answer
    In the Arrhenius plot of ln k Vs\[\frac{1}{T}\], a linear plot is obtained with a slope of \[-2\times {{10}^{4}}K.\] The energy of activation of the reaction (in\[kJ\text{ }mol{{e}^{-1}}\]) is (R value is\[8.3J\text{ }{{K}^{-1}}mo{{l}^{-1}}\]) 

    A) 83    

    B) 166  

    C) 249                  

    D) 332

    Correct Answer: B

    Solution :

    [b] \[k=A{{e}^{-{{E}_{a}}}}^{/RT}\] \[lnk=lnA-{{E}_{a}}/RT\] For ln k Vs 1/T In A= intercept \[-{{E}_{a}}/R=slope=-2\times {{10}^{4}}K\] \[\therefore {{E}_{a}}=8.3\times 2\times {{10}^{4}}J\,mo{{l}^{-1}}\] \[=16.6\times {{10}^{4}}J\,mo{{l}^{-1}}\text{ }or\text{ }166\,kJ\,mo{{l}^{-1}}\]


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