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NEET Chemistry Chemical Kinetics / रासायनिक बलगतिकी Question Bank Self Evaluation Test - Chemical Kinetics

  • question_answer
    Consider the reaction \[A\to 2B+C,\Delta H=-15\]kcal. The energy of activation of backward reaction is\[20\text{ }kcal\text{ }mo{{l}^{-1}}\]. In presence of catalyst the energy of activation of forward reaction is \[3\text{ }kcal\text{ }mo{{l}^{-1}}\]. At 400 K. the catalyst causes the rate of the reaction to increase by the number of times equal to                 

    A) \[{{e}^{3.5}}\]

    B) \[{{e}^{2.5}}\]

    C) \[{{e}^{-\,2.5}}\]

    D) \[{{e}^{2.303}}\]

    Correct Answer: B

    Solution :

    [b] \[{{E}_{a}}(f)-{{E}_{a}}(b)=\Delta H=15\,k\,cal\] \[\Rightarrow {{E}_{a}}(f)=-15+20=5\,kcal\] \[\frac{k(catalyst)}{k}={{e}^{\frac{{{E}_{a}}-{{E}_{a(\,catalyst)}}}{RT}}}\] \[={{e}^{\frac{(5-3)\times {{10}^{3}}}{2\times 400}}}={{e}^{2.5}}\]


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