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NEET Chemistry Chemical Kinetics / रासायनिक बलगतिकी Question Bank Self Evaluation Test - Chemical Kinetics

  • question_answer
    In the reaction of formation of sulphur trioxide by contact process \[2S{{O}_{2}}+{{O}_{2}}\rightleftharpoons 2S{{O}_{3}}\] the rate of reaction was measured as \[\frac{d[{{O}_{2}}]}{dt}=-2.5\times {{10}^{-4}}mol{{L}^{-1}}{{s}^{-1}}\]. The rate of reaction is terms of \[[S{{O}_{2}}]\] in \[mol\text{ }{{L}^{-1}}{{s}^{-1}}\] will be:

    A) \[-1.25\times {{10}^{-4}}\]       

    B) \[-2.50\times {{10}^{-4}}\]

    C) \[-3.75\times {{10}^{-4}}\]       

    D) \[-5.00\times {{10}^{-4}}\]

    Correct Answer: D

    Solution :

    [d] From rate law \[-\frac{1}{2}\frac{dS{{O}_{2}}}{dt}=-\frac{d{{O}_{2}}}{dt}=\frac{1}{2}\frac{dS{{O}_{3}}}{dt}\] \[\therefore -\frac{dS{{O}_{2}}}{dt}=-2\times \frac{d{{O}_{2}}}{dt}\] \[=-2\times 2.5\times {{10}^{-4}}\] \[=-5\times {{10}^{-4}}mol\,{{L}^{-1}}{{s}^{-1}}\]


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