A) 10 g
B) 40 g
C) 80 g
D) 20 g
Correct Answer: D
Solution :
[d] Using the relation \[\left[ A \right]={{\left[ A \right]}_{0}}{{(1/2)}^{n}}\][n =number of half-lives \[T=n\times {{t}_{1/2}}\] Here, \[n=\frac{7.5}{2.5}=3\] \[\therefore [A]=160\times {{\left( \frac{1}{2} \right)}^{3}}=160\times \frac{1}{8}=20g\]You need to login to perform this action.
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