A) \[-123{}^\circ C\]
B) \[327{}^\circ C\]
C) \[32.7{}^\circ C\]
D) \[+23{}^\circ C\]
Correct Answer: B
Solution :
[b] \[\frac{E'a}{{{T}_{1}}}=\frac{E'a}{{{T}_{2}}}=\frac{10}{300}=\frac{20}{{{T}_{2}}}\] \[\therefore \text{ }{{\text{T}}_{2}}=600K=327{}^\circ C\]You need to login to perform this action.
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