A) \[-\frac{d[{{H}_{2}}]}{dt}=-\frac{d[{{I}_{2}}]}{dt}=-\frac{d[HI]}{dt}\]
B) \[\frac{d[{{H}_{2}}]}{dt}=\frac{d[{{I}_{2}}]}{dt}=\frac{1}{2}\frac{d[HI]}{dt}\]
C) \[\frac{1}{2}\frac{d[{{H}_{2}}]}{dt}=\frac{1}{2}\frac{d[{{I}_{2}}]}{dt}=-\frac{d[HI]}{dt}\]
D) \[-2\frac{d[{{H}_{2}}]}{dt}=-2\frac{d[{{I}_{2}}]}{dt}=\frac{d[HI]}{dt}\]
Correct Answer: D
Solution :
[d] rate of appearance of \[HI=\frac{1}{2}\frac{d[HI]}{dt}\] rate of disappearance of \[{{H}_{2}}=\frac{-d[{{H}_{2}}]}{dt}\] rate of disappearance of \[{{I}_{2}}=\frac{-d[{{I}_{2}}]}{dt}\] hence \[\frac{-d[{{H}_{2}}]}{dt}=-\frac{d[{{I}_{2}}]}{dt}=\frac{1}{2}\frac{d[HI]}{dt}\] or \[-\frac{2d[{{H}_{2}}]}{dt}=-\frac{2d[{{I}_{2}}]}{dt}=\frac{d[HI]}{dt}\]
You need to login to perform this action.
You will be redirected in
3 sec
