A) \[-1.25\times {{10}^{-4}}\]
B) \[-2.50\times {{10}^{-4}}\]
C) \[-3.75\times {{10}^{-4}}\]
D) \[-5.00\times {{10}^{-4}}\]
Correct Answer: D
Solution :
[d] From rate law \[-\frac{1}{2}\frac{dS{{O}_{2}}}{dt}=-\frac{d{{O}_{2}}}{dt}=\frac{1}{2}\frac{dS{{O}_{3}}}{dt}\] \[\therefore -\frac{dS{{O}_{2}}}{dt}=-2\times \frac{d{{O}_{2}}}{dt}\] \[=-2\times 2.5\times {{10}^{-4}}\] \[=-5\times {{10}^{-4}}mol\,{{L}^{-1}}{{s}^{-1}}\]You need to login to perform this action.
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