NEET Chemistry Chemical Kinetics / रासायनिक बलगतिकी Question Bank Self Evaluation Test - Chemical Kinetics

  • question_answer
    For the reaction, \[3A+2B\to C+D\], the differential rate law can be written as:

    A) \[\frac{1}{3}\frac{d[A]}{dt}=\frac{d[C]}{dt}=k{{[A]}^{n}}{{[B]}^{m}}\]

    B) \[-\frac{d[A]}{dt}=\frac{d[C]}{dt}=k{{[A]}^{n}}{{[B]}^{m}}\]

    C) \[+\frac{1}{3}\frac{d[A]}{dt}=-\frac{d[C]}{dt}=k{{[A]}^{n}}{{[B]}^{m}}\]

    D) \[-\frac{1}{3}\frac{d[A]}{dt}=\frac{d[C]}{dt}=k{{[A]}^{n}}{{[B]}^{m}}\]

    Correct Answer: D

    Solution :

    [d] For the reaction \[3A+2B\xrightarrow{{}}C+D\] Rate of disappearance of A = Rate of appearance of C reaction \[=-\frac{1}{3}\frac{d[A]}{dt}=\frac{d[C]}{dt}=k{{[A]}^{n}}{{[B]}^{m}}\]


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