NEET Chemistry Chemical Kinetics / रासायनिक बलगतिकी Question Bank Self Evaluation Test - Chemical Kinetics

  • question_answer
    The rate law for a reaction between the substances A and B is given by rate \[=k{{[A]}^{n}}{{[B]}^{m}}\] On doubling the concentration of A and halving the concentration of B, the ratio of the new rate to the earlier rate of the reaction will be as

    A) \[\left( m+n \right)\]                    

    B) \[\left( n-m \right)\]

    C) \[{{2}^{\left( n+m \right)}}\]                  

    D) \[\frac{1}{{{2}^{\left( m+n \right)}}}\]

    Correct Answer: C

    Solution :

    [c] \[Rat{{e}_{1}}=k{{[A]}^{n}}{{[B]}^{m}};\,\,Rat{{e}_{2}}=k{{[2A]}^{n}}{{[{\scriptstyle{}^{1}/{}_{2}}B]}^{m}}\] \[\therefore \frac{Rat{{e}_{2}}}{Rat{{e}_{1}}}=\frac{k{{[2A]}^{n}}{{[{\scriptstyle{}^{1}/{}_{2}}B]}^{m}}}{k{{[A]}^{n}}{{[B]}^{m}}}\] \[={{[2]}^{n}}{{[{\scriptstyle{}^{1}/{}_{2}}]}^{m}}={{2}^{n}}.\,{{2}^{-m}}={{2}^{n-m}}\]


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