NEET Chemistry Chemical Kinetics / रासायनिक बलगतिकी Question Bank Self Evaluation Test - Chemical Kinetics

  • question_answer
    The reaction \[A\to B\] follows first order kinetics. The time taken for 0.8 mole of A to produce 0.6 mole of B is 1 hour. What is the time taken for conversion of 0.9 mole of A to produce 0.675 mole of B?

    A) 2 hours                         

    B) 1 hour

    C) 0.5 hour           

    D) 0.25 hour

    Correct Answer: B

    Solution :

    [b]  \[A\to B\] For a first order reaction Given \[a=0.8\text{ }mol,\left( a-x \right)=0.8-0.6=0.2\] \[k=\frac{2.303}{1}log\frac{0.8}{0.2}or=2.303\,log4\] again \[a=0.9,a-x=0.9-0.675=0.225\] \[k=\frac{2.303}{t}\log \frac{0.9}{0.225}\] \[2.303log4=\frac{2.303}{t}log4\] Hence t=1 hour


You need to login to perform this action.
You will be redirected in 3 sec spinner