A) 1
B) 2
C) 0
D) 3
Correct Answer: B
Solution :
[b] \[pH=2\,;{{r}_{1}}=k\times {{({{10}^{-2}})}^{n}}\,\{Q[{{H}^{+}}]={{10}^{-pH}}\}\] \[pH=1;{{r}_{2}}=k\times {{({{10}^{-1}})}^{n}}\] Given \[{{r}_{2}}=100\text{ }{{r}_{1}}\] \[\Rightarrow {{\left( \frac{{{10}^{-1}}}{{{10}^{-2}}} \right)}^{n}}=100\] \[{{10}^{n}}=100\] \[\therefore n=2\]You need to login to perform this action.
You will be redirected in
3 sec