A) 0.012
B) 0.024
C) \[2\times {{10}^{-3}}\]
D) \[2\times {{10}^{-4}}\]
Correct Answer: D
Solution :
[d] Rate of reaction \[=\frac{d[A]}{dt}\] Given, \[{{[A]}_{initial}}=0.50\,M\] \[{{[A]}_{final}}=0.38\,M\] \[dt=10\text{ }min=600\text{ }sec\] \[d\left[ A \right]=0.12\] \[Rate=\frac{0.12}{600}=2\times {{10}^{-4}}M\,{{s}^{-1}}\]You need to login to perform this action.
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