A) \[{{e}^{3.5}}\]
B) \[{{e}^{2.5}}\]
C) \[{{e}^{-\,2.5}}\]
D) \[{{e}^{2.303}}\]
Correct Answer: B
Solution :
[b] \[{{E}_{a}}(f)-{{E}_{a}}(b)=\Delta H=15\,k\,cal\] \[\Rightarrow {{E}_{a}}(f)=-15+20=5\,kcal\] \[\frac{k(catalyst)}{k}={{e}^{\frac{{{E}_{a}}-{{E}_{a(\,catalyst)}}}{RT}}}\] \[={{e}^{\frac{(5-3)\times {{10}^{3}}}{2\times 400}}}={{e}^{2.5}}\]You need to login to perform this action.
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