question_answer

When a biochemical reaction is carried out in laboratory in the absence of enzyme then rate of reaction obtained is \[{{10}^{-6}}\] times, then activation energy of reaction in the presence of enzyme is

A) \[\frac{6}{RT}\]

B) different from \[{{E}_{a}}\] obtained in laboratory,

C) P is required

D) can't say anything

Correct Answer: B

Solution :

[b] The presence of enzyme (catalyst) increases the speed of reaction by lowering the energy barrier, i.e., a new path is followed with lower activation energy. Here \[{{E}_{T}}\] is the threshold energy. \[{{E}_{a}}\] and \[{{E}_{a1}}\] is energy of activation of reaction in absence and presence of catalyst respectively.