A) \[-\frac{{{E}_{a}}}{2.303R}\]
B) \[\frac{{{E}_{a}}}{R}\]
C) \[-\frac{R}{2.303{{E}_{a}}}\]
D) None of these
Correct Answer: A
Solution :
[a] Arrhenius equation is given by \[k=A{{e}^{-{{E}_{a}}}}^{/RT}\] Taking log on both sides, we get \[\log k=\operatorname{logA}-\frac{{{E}_{a}}}{2.303RT}\] Arrhenius plot a graph between log k and \[\frac{1}{T}\] whose slope is \[\frac{-{{E}_{a}}}{2.303R}.\]
You need to login to perform this action.
You will be redirected in
3 sec
