NEET Chemistry Chemical Kinetics / रासायनिक बलगतिकी Question Bank Self Evaluation Test - Chemical Kinetics

  • question_answer
    The rate constant of a reaction with a virus is \[3.3\times {{10}^{-4}}{{s}^{-1}}\]. Time required for the virus to become 75% inactivated is

    A) 35 min                         

    B) 70 min

    C) 105 min           

    D) 17.5 min

    Correct Answer: B

    Solution :

    [b] \[{{t}_{1/2}}=\frac{0.693}{k}=2100s=35\,min\] \[{{t}_{75}}\]% \[=2{{t}_{1/2}}=2\times 35=70\,min\]


You need to login to perform this action.
You will be redirected in 3 sec spinner