A) 0
B) 1
C) 2
D) 3/2
Correct Answer: D
Solution :
[d] \[{{A}_{2}}+{{B}_{2}}\xrightarrow{{}}2AB\text{ };\] \[{{A}_{2}}\xrightarrow{{}}A+A\left( Fast \right);\] \[A+{{B}_{2}}\xrightarrow{{}}AB+B\left( Slow \right)\] Rate law \[=k\left[ A \right]\left[ {{B}_{2}} \right]\]put value of [A] from 1st reaction since A is intermediate \[\sqrt{k[{{A}_{2}}]}=A\] \[\therefore \] Rate law equation \[=k\sqrt{k[{{A}_{2}}]}[{{B}_{2}}]\] \[\therefore \,Order=\frac{1}{2}+1=\frac{3}{2}\]
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