A) evaluating rate constant at standard temperature
B) evaluating velocities of reaction at two different temperatures
C) evaluating rate constants at two different temperatures
D) changing concentration of reactants
Correct Answer: C
Solution :
[c] We know that the activation energy of chemical reaction is given by formula \[=\frac{{{k}_{2}}}{{{k}_{1}}}=\frac{{{E}_{a}}}{2.303R}\left( \frac{{{T}_{2}}-{{T}_{1}}}{{{T}_{1}}{{T}_{2}}} \right)\], where \[{{k}_{1}}\] is the rate constant at temperature \[{{T}_{1}}\] and \[{{k}_{2}}\] is the rate constant at temperature \[{{T}_{2}}\] and \[{{E}_{\text{a}}}\] is the activation energy. Therefore activation energy of chemical reaction is determined by evaluating rate constant at two different temperatures.
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