A) \[Ba>Sr>\]Mg; atomic radius
B) \[F>O>N:\] first ionization enthalpy
C) \[Cl>F>I;\] electron affinity
D) \[O>Se>Te;\] electronegativity
Correct Answer: B
Solution :
[b] On moving along the period, ionization enthalpy increases. In second period, the order of ionization enthalpy should be as follows : \[F>O>N\] But N has half-filled structure, therefore, it is more stable than O. That's why its ionization enthalpy is higher than O. Thus, the correct order of IE is \[F>N>O.\]You need to login to perform this action.
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