Consider the following ionisation reactions: |
I.E.\[\left( kJ\text{ }mo{{l}^{-1}} \right)\] I.E. \[\left( kJ\text{ }mo{{l}^{-1}} \right)\] |
\[A(g)\to {{A}^{+}}(g)+{{e}^{-}},\,\,{{A}_{1}}\,\,A(g)~\to {{A}^{+}}(g)+{{e}^{-}},\,\,{{A}_{1}}\] |
\[{{B}^{+}}(g)\to {{B}^{2+}}(g)+{{e}^{-}},\,\,{{B}_{2}}C(g)\to {{C}^{+}}(g)+{{e}^{-}},\,\,{{C}_{1}}\] |
\[{{C}^{+}}(g)\to {{C}^{2+}}(g)+{{e}^{-}},\,\,{{C}_{1}}\,{{C}^{2+}}(g)\to {{C}^{3+}}(g)+{{e}^{-}},\,\,{{C}_{3}}\] |
A) \[{{C}_{3}}>{{B}_{2}}>{{A}_{1}}\]
B) \[{{B}_{1}}>{{A}_{1}}>{{C}_{1}}\]
C) \[{{C}_{3}}>{{C}_{2}}>{{B}_{2}}\]
D) \[{{B}_{2}}>{{C}_{3}}>{{A}_{1}}\]
Correct Answer: D
Solution :
[d] |
\[A\Rightarrow H\,(1{{s}^{1}})\] |
\[B\Rightarrow He\,(1{{s}^{2}})\] |
\[C\Rightarrow Li\,(1{{s}^{2}}2{{s}^{1}})\] |
\[{{A}_{1}}=I{{E}_{1}}(A){{B}_{2}}=I{{E}_{2}}(B)\] |
\[{{B}_{1}}=I{{E}_{1}}(B){{C}_{2}}=I{{E}_{2}}(C)\] |
\[{{C}_{1}}=I{{E}_{1}}(C){{C}_{3}}=I{{E}_{3}}(C)\] |
\[{{B}_{1}}>{{A}_{1}}>{{C}_{1}}{{C}_{3}}>{{B}_{2}}>{{A}_{1}}\] |
\[He>H>LiL{{i}^{2+}}H{{e}^{+}}H\] |
\[1{{s}^{2}}1{{s}^{1}}2{{s}^{1}}\ 1{{s}^{1}}1{{s}^{1}}1{{s}^{1}}\] |
\[{{C}_{3}}>{{C}_{2}}>{{B}_{2}}L{{i}^{2+}}L{{i}^{+}}H{{e}^{+}}\] |
\[1{{s}^{2}}\,1{{s}^{2}}\,1{{s}^{1}}\] |
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