question_answer

Coordination number of Cr is six. A complex with\[{{C}_{2}}O_{4}^{2-}\], en and superoxide \[O_{2}^{-}\] will be in the ratio to make complex \[{{[Cr{{({{C}_{2}}{{O}_{4}})}_{x}},{{(en)}_{y}}{{({{O}_{2}})}_{z}}]}^{-}}\]

A) x-1        y-1        z-1

B) x-1        y-1       z-2

C) x-1        y-2        z-2

D) x-2        y-1       z-1

Correct Answer: D

Solution :

[d] \[C{{r}^{3+}},{{C}_{2}}O_{4}^{2-},{{(en)}^{0}},{{O}_{2}}\] \[{{C}_{2}}O_{4}^{2-}\] and \[{{\left( en \right)}^{0}}\] are bidenate ligand. CN of \[C{{r}^{3+}}=6\],