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NEET Chemistry Coordination Chemistry Question Bank Self Evaluation Test - Co-ordination Compounds

  • question_answer
    The total number of possible isomers of the complex compound \[[C{{u}^{II}}{{(N{{H}_{3}})}_{4}}][P{{t}^{II}}C{{l}_{4}}]\] is

    A) 3                                 

    B) 6  

    C) 5                                 

    D) 4

    Correct Answer: D

    Solution :

    [d] For \[[C{{u}^{II}}{{(N{{H}_{3}})}_{4}}[P{{t}^{II}}C{{l}_{4}}]\]four isomers are possible which are\[[Cu{{(N{{H}_{3}})}_{4}}[PtC{{l}_{4}}]\], \[[CuC{{l}_{4}}],[Pt{{\left( N{{H}_{3}} \right)}_{4}}][PtC{{l}_{3}}\left( N{{H}_{3}} \right)][Cu{{\left( N{{H}_{3}} \right)}_{3}}Cl]\] and \[\left[ Pt{{\left( N{{H}_{3}} \right)}_{3}}Cl \right]\left[ Cu\left( N{{H}_{3}} \right)C{{l}_{3}} \right]\]


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