A) zero
B) one
C) three
D) four
Correct Answer: A
Solution :
[a] \[Ni{{\left( CO \right)}_{4}}.\]The O. S. of Ni is zero. Electronic configuration is \[\left[ Ar \right]3{{d}^{8}}4{{s}^{2}}4{{p}^{0}}\] . In presence of strong ligand CO the paring of electrons take place and electronic configuration will be\[\left[ Ar \right]3{{d}^{10}}4{{s}^{0}}4{{p}^{0}}\]. Hence unpaired electrons is zero.You need to login to perform this action.
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