A) \[N{{a}_{2}}[CrC{{l}_{5}}({{H}_{2}}O)]\]
B) \[N{{a}_{3}}[CrC{{l}_{6}}]\]
C) \[\left[ Cr{{\left( {{H}_{2}}O \right)}_{5}}Cl \right]C{{l}_{2}}\text{ }\!\!~\!\!\text{ }\]
D) \[\left[ Cr{{\left( {{H}_{2}}O \right)}_{6}} \right]C{{l}_{3}}\]
Correct Answer: D
Solution :
[d] More equivalents of \[AgN{{O}_{3}}\] aqueous solution will be consumed if complex will furnish more \[C{{l}^{-}}\] ions in solution. Hence complex \[[Cr{{\left( {{H}_{2}}O \right)}_{6}}]\,C{{l}_{3}}\] will consume more equivalents of aqueous solution of \[AgN{{O}_{3}}\].
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