\[{{K}_{3}}\left[ Fe{{\left( CN \right)}_{6}} \right]\] (K), \[\left[ Co{{\left( N{{H}_{3}} \right)}_{6}} \right]C{{l}_{3}}\text{ }\left( L \right),\] |
\[N{{a}_{3}}\left[ Co{{\left( oxalate \right)}_{3}} \right]\] (M), \[[Ni{{({{H}_{2}}O)}_{6}}]C{{l}_{2}})(N),\] |
\[{{K}_{2}}[Pt{{\left( CN \right)}_{4}}\left( O \right)\] and \[[Zn{{({{H}_{2}}O)}_{6}}]{{(N{{O}_{3}})}_{2}}(P)\] the |
diamagnetic complexes are |
A) K, L, M, N
B) K, M, O, P
C) L, M, O, P
D) L, M, N, O
Correct Answer: C
Solution :
[c]Complex | No. of electrons in outer d orbital | No. of unpaired electrons (s) |
\[{{[Fe{{(CN)}_{6}}]}^{3-}}\] | \[3{{d}^{5}}\] | 1 (\[C{{N}^{-}}\] causes pairing of electrons) |
\[{{[Co{{(N{{H}_{3}})}_{6}}]}^{3-}}\] | \[3{{d}^{6}}\] | 0 |
\[{{[Co{{(OX)}_{3}}]}^{3-}}\] | \[3{{d}^{6}}\] | 0 |
\[{{[Ni{{({{H}_{2}}O)}_{6}}]}^{2+}}\] | \[3{{d}^{8}}\] | 2 |
\[{{[Pt{{(CN)}_{4}}]}^{2-}}\] | \[5{{d}^{8}}\] | 0 (\[C{{N}^{-}}\] cause pairing of electrons) |
\[{{[Zn{{({{H}_{2}}O)}_{6}}]}^{2+}}\] | \[3{{d}^{10}}\] | 0 |
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