A) \[{{d}^{2}}s{{p}^{3}}\] hybridised and diamagnetic
B) \[s{{p}^{3}}{{d}^{2}}\] hybridised and paramagnetic
C) \[s{{p}^{3}}{{d}^{2}}\] hybridised and diamagnetic
D) \[{{d}^{2}}s{{p}^{3}}\] hybridised and paramagnetic
Correct Answer: D
Solution :
[d] \[F{{e}^{2+}}:\] Complex is paramagnetic due topresence of unpaired electron at \[O_{2}^{-}\] i.e., superoxide acting as ligand.You need to login to perform this action.
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