A) \[t,\,\,0.5\]
B) \[t,\,\,1.0\]
C) \[t,\,\,1.5\]
D) \[{{t}^{2}},\,\,2.0\]
Correct Answer: A
Solution :
[a] Comparing \[({{x}_{AM}})t=100\,[1+0.5\,t]\,\cos {{\omega }_{c}}t\] for \[0<t<1\] with standard AM signal \[{{x}_{AM}}={{E}_{c}}[1+{{m}_{a}}\cos \,{{\omega }_{m}}t]\,\cos {{\omega }_{c}}t\] We have modulating signal t and \[{{m}_{a}}=0.5.\]You need to login to perform this action.
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