A) \[1.28\pi \times {{10}^{3}}k{{m}^{2}}\]
B) \[2\pi \times {{10}^{4}}k{{m}^{2}}\]
C) \[3.1\times {{10}^{4}}k{{m}^{2}}\]
D) \[6\pi \times {{10}^{4}}k{{m}^{2}}\]
Correct Answer: A
Solution :
[a] Area covered by T.V. signals \[A=2\pi hR=2\times 3.14\times 100\times 6.4\times {{10}^{6}}\] \[=128\pi \times {{10}^{8}}\] \[\Rightarrow \,\,\,\,\,\,\,\,\,\,\,\,A=1.28\pi \times {{10}^{3}}k{{m}^{2}}\]You need to login to perform this action.
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