A) \[{{C}_{m}}(t)=A(1+\sin {{\omega }_{m}}t)\,\sin {{\omega }_{c}}t\] and 2
B) \[{{C}_{m}}(t)=A(1+\sin {{\omega }_{m}}t)\,\sin {{\omega }_{m}}t\] and 1
C) \[{{C}_{m}}(t)=A(1+\sin {{\omega }_{m}}t)\,\sin {{\omega }_{c}}t\] and 1
D) \[{{C}_{m}}(t)=A(1+\sin {{\omega }_{c}}t)\,\sin {{\omega }_{m}}t\] and 2
Correct Answer: C
Solution :
[c] Modulation index \[{{m}_{a}}=\frac{{{E}_{m}}}{{{E}_{c}}}=\frac{A}{A}=1\] Equation of modulated signal \[[{{C}_{m}}(t)]\] \[={{E}_{(C)}}+{{m}_{a}}{{E}_{(C)}}\sin {{\omega }_{m}}t=A(1+\sin {{\omega }_{m}}t)\sin {{\omega }_{c}}t\] (As\[{{E}_{(C)}}=A\,\sin \,{{\omega }_{C}}t\])You need to login to perform this action.
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