A) \[94\,V\]
B) \[104.5\,V\]
C) \[114.4\,V\]
D) \[124\,V\]
Correct Answer: B
Solution :
[b] \[{{P}_{t}}={{P}_{c}}\left[ 1+\frac{{{m}_{a}}^{2}}{2} \right]\] \[\Rightarrow \,\,\,\,\,\,\,\frac{{{V}^{2}}_{rms}}{2}=\frac{{{V}^{2}}_{c}}{2}\,\,\left[ 1+\frac{{{m}_{a}}^{2}}{2} \right]\] \[{{V}^{2}}_{rms}={{V}^{2}}_{c}\left[ 1+\frac{{{m}_{a}}^{2}}{2} \right]\] \[\Rightarrow \,\,\,\,\,{{V}_{rms}}={{V}_{c}}\sqrt{1+\frac{{{m}_{a}}^{2}}{2}}\Rightarrow {{V}_{rms}}=100\sqrt{1+\frac{{{(0.3)}^{2}}}{2}}\] \[=104.5\,\,volts.\]
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