A) \[10.25\,kW\]
B) \[11.25\,kW\]
C) \[12.75\,kW\]
D) \[17\,kW\]
Correct Answer: B
Solution :
[b] \[{{P}_{c}}=\frac{{{E}_{c}}^{2}}{2}=10\,kW\] \[{{m}_{a}}=\sqrt{m_{1}^{2}+m_{2}^{2}}=\sqrt{{{0.30}^{2}}+{{0.40}^{2}}}=0.50\] \[\therefore \,\,\,\,\,\,\,\,{{P}_{t}}={{P}_{c}}\left( 1+\frac{{{m}_{{{a}^{2}}}}}{2} \right)=10\left( 1+\frac{{{\left( 0.5 \right)}^{2}}}{2} \right)\] \[=11.25\,kW\]
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