2. Questions Bank
  3. JEE Main & Advanced
  4. Physics
  5. Communication System / संचार तंत्र

JEE Main & Advanced Physics Communication System / संचार तंत्र Question Bank Self Evaluation Test - Communication System

  • question_answer
    12 signals each band limited to \[5\text{ }kHz\] are to be transmitted by frequency-division multiplexer. If AM-SSB modulation guard band of \[\text{1 }kHz\] is used then the bandwidth of multiplexed signal is

    A) \[\text{101 }kHz\]

    B) \[\text{99 }kHz\]

    C) \[\text{84 }kHz\]

    D) \[\text{71 }kHz\]

    Correct Answer: D

    Solution :

    [d] Total signal B.W\[=12\times 5=60\text{ }kHz\] 11 guard band are required between 12 signal \[\therefore \] guard bandwidth \[=11\times 1\,kHz=11\,kHz\] \[\therefore \] total bandwidth \[=60+11=71\,kHz\]


You need to login to perform this action.
You will be redirected in 3 sec spinner