A) \[-\frac{\sqrt{3}}{2}\]
B) \[-\frac{1}{\sqrt{2}}\]
C) \[\frac{1}{\sqrt{2}}\]
D) \[\frac{\sqrt{3}}{2}\]
Correct Answer: B
Solution :
\[\sin \,\left\{ \left( {{\omega }^{13}}+{{\omega }^{2}} \right)\pi +\frac{\pi }{4} \right\}\] \[=\sin \,\left\{ \left( \omega +{{\omega }^{2}} \right)\pi +\frac{\pi }{4} \right\}=\sin \left( -\pi +\frac{\pi }{4} \right)\] \[=-\,sin\frac{\pi }{4}=-\frac{1}{\sqrt{2}}\]
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