A) \[-i\]
B) \[1\]
C) \[-1\]
D) \[i\]
Correct Answer: C
Solution :
Consider \[|\bar{z}\omega ||\bar{z}||\omega |=|z||\omega |=|z\omega |=1\] Consider \[Arg\,(\bar{z}\omega )=\arg (\bar{z})+arg(\omega )=-arg(z)+arg\omega \] \[=-\frac{\pi }{2}\,\,\,\therefore \,\,\bar{z}\omega =-1\]You need to login to perform this action.
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