A) \[1+4i\]
B) \[4+i\]
C) \[1-i\]
D) \[-1-i\]
Correct Answer: A
Solution :
\[\operatorname{Let}\, z=a+bi\] \[\Rightarrow \,\,\,\bar{z} = a\,- bi\] \[\therefore \,\,\,\,i\bar{z}-iz=i[(a\,-bi)-(a+bi)]1=5\] \[\Rightarrow \,\,\,\,i\left[ -\,2bi \right]=5\] \[\Rightarrow \,\,\,\,b=\frac{5}{2}\] So from figure it is clear that \[\operatorname{x}=1,\,\,\,y=\,\frac{5}{2}+\frac{3}{2}=4\] \[{{z}_{2}}=1+4\,i\]You need to login to perform this action.
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