then
A) \[y=6\]
B) \[y=5\]
C) \[y=\sqrt{6}\]
D) \[y=\sqrt{5}\]
Correct Answer: D
Solution :
\[\Rightarrow \,\,\,(y\,-2)(y+2)=1\Rightarrow \,\,{{y}^{2}}-4=1\,\,\,\Rightarrow \,\,{{y}^{2}}=5\] \[\therefore \,\,\,y=\pm \sqrt{5}\,\,since\,\,y>0\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\therefore y=\sqrt{5}\]
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