A) 3 unit and 4 unit
B) 6 unit and 4 unit
C) 3 unit and 8 unit
D) 6 unit and 8 unit
Correct Answer: D
Solution :
[d] Equation of circle having radius r and centre (3, 4) is \[={{(x-3)}^{2}}+{{(y-4)}^{2}}={{r}^{2}}\] If it is passing through (0, 0) \[\therefore \,\,\,\,{{(0-3)}^{2}}+{{(0-4)}^{2}}={{r}^{2}}\] \[\Rightarrow {{r}^{2}}=25\] equation of circle is \[{{(x-3)}^{2}}+{{(y-4)}^{2}}=25\] Putting y=0 \[\therefore \] x = 6 unit = interception x-axis intercept on y axis (Putting x = 0) is \[y=8\] unitYou need to login to perform this action.
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