JEE Main & Advanced Mathematics Conic Sections Question Bank Self Evaluation Test - Conic Sections

  • question_answer
    The line joining (5, 0) to is divided internally in the ratio 2 : 3 at P. If \[\theta \] varies, then the locus of P is

    A) A pair of straight lines

    B) A circle

    C) A straight line

    D) None of these

    Correct Answer: B

    Solution :

    [b] Let \[P(x,y)\] be the point dividing the join of A and B in the ratio 2 : 3 internally, then \[x=\frac{20\cos \theta +15}{5}=4\cos \theta +3\] \[\Rightarrow \cos \theta =\frac{x-3}{4}\]                          ?. (i) \[y=\frac{20\sin \theta +0}{5}=4\sin \theta \Rightarrow \sin \theta =\frac{y}{4}\]    ? (ii) Squaring and adding (i) and (ii), we get the required locus \[{{(x-3)}^{2}}+{{y}^{2}}=16,\] which is a circle.


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