A) \[{{x}^{2}}+{{y}^{2}}-4x+4y+4=0\]
B) \[{{x}^{2}}+{{y}^{2}}-4x-4y+4=0\]
C) \[{{x}^{2}}+{{y}^{2}}+4x-4y-4=0\]
D) \[{{x}^{2}}+{{y}^{2}}+4x+4y-4=0\]
Correct Answer: B
Solution :
[b] The equation of circle, which touches both the axes, is given by \[{{x}^{2}}+{{y}^{2}}-2rx-2ry+{{r}^{2}}=0\] ? (i) Now the centre (r, r) of this circle lies on the line \[x+y=4\] \[r+r=4\Rightarrow r=2\] \[\therefore \] Put value of r in Eq. (i). We get \[{{x}^{2}}+{{y}^{2}}-4x-4y+4=0\] which is required equation of circle,
You need to login to perform this action.
You will be redirected in
3 sec
