A) 10 unit
B) 9 unit
C) 8 unit
D) 6 unit
Correct Answer: A
Solution :
[a] \[\frac{{{x}^{2}}}{25}+\frac{{{y}^{2}}}{9}=1\] |
Put \[x=3\] |
\[\frac{9}{25}+\frac{{{y}^{2}}}{9}=1\] |
\[y=\frac{12}{5}\] |
\[P=(3,12/5)\] |
\[r=PO=\sqrt{{{(4-3)}^{2}}+{{\left( 0-\frac{12}{5} \right)}^{2}}}\] |
\[=17/5\] |
\[S=PO'=\sqrt{[-4-3]+{{\left( 0-\frac{12}{5} \right)}^{2}}}\] |
\[=33/5\] |
\[r+s=\frac{17}{5}+\frac{33}{5}=\frac{50}{5}=10\,\,units\] |
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