A) 4
B) 5
C) 6
D) 7
Correct Answer: B
Solution :
[b] Coordinates of the centre of given circle \[=(\alpha ,\,\,\alpha )\] and radius \[=\sqrt{{{(\alpha )}^{2}}+{{(\alpha )}^{2}}-{{\alpha }^{2}}}=\sqrt{{{\alpha }^{2}}}=\alpha \] \[\therefore {{(\alpha -5)}^{2}}+{{(\alpha )}^{2}}={{(\alpha )}^{2}}\] \[\Rightarrow {{\alpha }^{2}}+25-10\alpha =0\Rightarrow {{(\alpha -5)}^{2}}=0\Rightarrow \alpha =5\] Then, other root will always real.You need to login to perform this action.
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